How to store all dates in an array present in between given two dates in JavaScript ?

Last Updated : 3 Jul, 2024

Given two dates the task is to get the array of dates between the two given dates using JavaScript. 

Below are the following approaches:

Table of Content

Approach 1: Using push() Method

  • Select the first and last date and store it in a variable.
  • Check if the start date is less than the stop date then push the current date in an array and increment its value by 1 day.
  • Repeat the above step until currentDate equal to the last date.

Example: In this example, the array of dates is determined by the above approach. 

JavaScript 
Date.prototype.addDay = function (days) {
    let date = new Date(this.valueOf());
    date.setDate(date.getDate() + days);
    return date;
}

function getDate(strDate, stpDate) {
    let dArray = new Array();
    let cDate = strDate;
    while (cDate <= stpDate) {

        // Adding the date to array
        dArray.push(new Date(cDate) + '<br>');

        // Increment the date by 1 day
        cDate = cDate.addDay(1);
    }
    return dArray;
}

function GFG_Fun() {
    let startDate = new Date();

    // Making lastDate equal to 4 more days
    // from startDate.
    let endDate = startDate.addDay(4);
    console.log(getDate(startDate, endDate));
}
GFG_Fun();

Output
[
  'Tue Jul 18 2023 18:59:06 GMT+0000 (Coordinated Universal Time)<br>',
  'Wed Jul 19 2023 18:59:06 GMT+0000 (Coordinated Universal Time)<br>',
  'Thu Jul 20 2023 18:59:06 GMT+0000 (Coordinated Univ...

Approach 2: Using for loop and push() Method

  • Get the first and last date and store it into a variable.
  • Calculate 1 day equivalent in milliseconds called _1Day.
  • Set a variable equal to the start date, called ms
  • Push ms (milli-seconds) in form of a date in an array and increment its value by _1Day.
  • Repeat the above step until ms is equal to the last date.

Example: In this example, the array of dates is determined by the above approach. 

JavaScript 
Date.prototype.addDay = function (days) {
    let date = new Date(this.valueOf());
    date.setDate(date.getDate() + days);
    return date;
};

function getDates(date1, date2) {
    let _1Day = 24 * 3600 * 1000;

    // Date[] keeps all the dates
    let dates = [];

    for (let ms = date1.getTime(), last = date2.getTime();
        ms <= last; ms += _1Day) {
        dates.push(new Date(ms));
    }

    return dates;
}

function GFG_Fun() {
    let startDate = new Date();

    // Making lastDate equal to 4 more days
    // from startDate
    let endDate = startDate.addDay(4);
    console.log(getDates(startDate, endDate));
}

GFG_Fun();

Output
[
  2023-07-18T19:12:03.831Z,
  2023-07-19T19:12:03.831Z,
  2023-07-20T19:12:03.831Z,
  2023-07-21T19:12:03.831Z,
  2023-07-22T19:12:03.831Z
]

Approach 3: Using concat method

The function getAllDates uses a for loop to iterate through dates between startDate and endDate, incrementing by one day each iteration. Dates are then concatenated into an array.

Example:

JavaScript 
function getAllDates(startDate, endDate) {
    let dates = [];
    for (let date = new Date(startDate); date <= endDate;
        date.setDate(date.getDate() + 1)) {
        dates = dates.concat(new Date(date));
    }
    return dates;
}


const startDate = new Date('2023-01-01');
const endDate = new Date('2023-01-10');

const result = getAllDates(startDate, endDate);
console.log(result);

Output
[
  2023-01-01T00:00:00.000Z,
  2023-01-02T00:00:00.000Z,
  2023-01-03T00:00:00.000Z,
  2023-01-04T00:00:00.000Z,
  2023-01-05T00:00:00.000Z,
  2023-01-06T00:00:00.000Z,
  2023-01-07T00:00:00.000Z,
  ...
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